Find the intercepts of y=x^4-10x^2-96
I can't seem to find them. I set y to zero to find x and set x to zero to find y. Thanks.
When x = 0, y = -96, so the y-intercept is (0,-96).
When y = 0, you have the quartic equation . Quartics are not easy to solve but you can let , so
. This factors to . Discard the imaginary solutions since the x-axis only takes on real values. Therefore the x-intercepts are (-4,0) and (4,0).