# Plane equation

• June 25th 2012, 08:46 PM
M.R
Plane equation
Hi,

I am trying to understand the following problem:

Find the parametric vector equation of the line through $(2, -1, 2)$ and perpendicular to the plane $x-2z=5$

The equation of the line is just the point + a vector in that direction. The answer shows:

$(2, -1, 2) + t(1, 0, 2)$

But how do you know it's perpendicular?
• June 25th 2012, 09:34 PM
M.R
Re: Plane equation
I figured it out!

From the equation of the plane, the coefficients yield the components of the normal vector
• June 26th 2012, 07:10 AM
biffboy
Re: Plane equation
So I think it should be t(1,0,-2) not t(1,0,2)
• June 26th 2012, 01:34 PM
M.R
Re: Plane equation
Yes, Thank you.