Results 1 to 5 of 5

Math Help - please how to find vertical and horizontal asymtopes

  1. #1
    Junior Member
    Joined
    Oct 2006
    From
    canada
    Posts
    68

    please how to find vertical and horizontal asymtopes

    Hello everybody, how are you doing?

    I'm having a hard time trying to figure out how to find vertical and horizontal asymtopes which if I'm not wrong are essentials to be able to graph a function correctly.
    So, could you please teach me how to find the vertical and horizontal asymtopes as in this example

    f(x) = 1/x+2 -1 , yeah I know is hard to read, I didn't know how to type it correctly, it is read: 1 over x -2 minus 1, (minus 1 is substrating both the denominador and the numerator).

    if you didn't understand how I wrote that exercise, you could also see it here

    http://www.accd.edu/sac/math/faculty.../PdfT1Rev2.pdf on question 4

    thank you so much.
    Last edited by jhonwashington; October 5th 2007 at 12:59 PM. Reason: wrong typing.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Oct 2007
    Posts
    8
    Asymptotes will occur where you have a denominator equal to 0. So the first one is obvious: when x = -2, you'll get one, so the equation of that asymptote is x = -2. Just rearrange the equation to get x in terms of f(x) and then you'll see the value of f(x) that produces the asympote. This equation will be y = f(a) where a is the x co-ordinate.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Rudipoo is correct so far. to summarize:

    we find vertical asymptotes by finding the x's for which the function is undefined.

    to find horizontal asymptotes, we find the limits \lim_{x \to \infty} f(x) AND \lim_{x \to - \infty}f(x), if either limit exists and is finite, then the finite number(s) is(are) the horizontal asymptotes.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,939
    Thanks
    338
    Awards
    1
    Quote Originally Posted by Jhevon View Post
    Rudipoo is correct so far. to summarize:

    we find vertical asymptotes by finding the x's for which the function is undefined.
    Is there a vertical asymptote for f(x) = \sqrt{x}? I note that f(-1) is not defined.

    -Dan
    Follow Math Help Forum on Facebook and Google+

  5. #5
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by topsquark View Post
    Is there a vertical asymptote for f(x) = \sqrt{x}? I note that f(-1) is not defined.

    -Dan
    Ah, point taken, maybe i should choose my words more carefully. i was speaking of rational functions as we have here. we have vertical asymptotes when the denominator is zero, that is, when the rational function is undefined
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 4
    Last Post: February 5th 2010, 12:56 PM
  2. Replies: 1
    Last Post: November 20th 2009, 07:33 PM
  3. Replies: 4
    Last Post: February 4th 2008, 09:26 PM
  4. Find Vertical and Horizontal Asymtot
    Posted in the Calculus Forum
    Replies: 1
    Last Post: April 2nd 2007, 04:02 AM
  5. Find Vertical and Horizontal Tangent
    Posted in the Calculus Forum
    Replies: 1
    Last Post: April 1st 2007, 11:19 PM

Search Tags


/mathhelpforum @mathhelpforum