Thread: how do i found the the height

The volume of a rectangular box is (x^3+6x^2+11x6). The
box is (x+3) cm long and (x+2) cm wide. How high is the box?

May I also add that this is in the long division section of the text book so i am assuming i will have to apply long division in it somewhere, i actually do not understand where to start, I am not looking for an answer, just ways that i can tackle the problem. thank you.

Originally Posted by waleedrabbani

The volume of a rectangular box is (x^3+6x^2+11x6). The
box is (x+3) cm long and (x+2) cm wide. How high is the box?

May I also add that this is in the long division section of the text book so i am assuming i will have to apply long division in it somewhere, i actually do not understand where to start, I am not looking for an answer, just ways that i can tackle the problem. thank you.

Divide the volume by (x+3).
You should get a reminder of zero.
Take the quotient and divide by (x+2) .
You should get a reminder of zero.
That quotient is the height.

Originally Posted by waleedrabbani

The volume of a rectangular box is (x^3+6x^2+11x6). The
box is (x+3) cm long and (x+2) cm wide. How high is the box?

May I also add that this is in the long division section of the text book so i am assuming i will have to apply long division in it somewhere, i actually do not understand where to start, I am not looking for an answer, just ways that i can tackle the problem. thank you.

As an alternative, for any prism I always remember that the volume is equal to the cross-sectional area multiplied by the height.

You are told the length is and the width is , so the cross sectional area is .

Therefore, you have



Now perform this long division to simplify the height