$\displaystyle e^a/(1+4e^a)=e^b/(1+4e^b)$

When I multiply each side by it's denominator I get:

$\displaystyle e^a+4e^a^+^b=e^b+4e^a^+^b$

hopefully I'm on the right track, then do I take the natural log of both sides? How does the natural log react in this situation with the addition? Do all the $\displaystyle e$'s cancel out?