You weren't asked to solve anything for x. Your answers for f of g and g of f are correct.
Find f of g and g of f if:
f(x)= 1/(2x-1)
g(x)=1-ln(x+1)
How do I solve for x? Is this what I should do? How should I present my answers? Please help!
f of g
1/(2*1-ln(x+1)-1)
1/(2-1-2ln(x+1))
1/(1-ln(x+1)(x+1))
x= -1
g of f
1-ln(1/(2x-1)+1)
1-ln(2x/(2x-1))
1=ln(2x/(2x-1))
e^{1}=2x/(2x-1)
e(2x-1)=2x
2xe-e=2x
2xe-2x=e
x(2e-2)=e
x=e/(2e)
x=1/2