Let and you will find that you have a cubic equation in
One solution of the equation is easy to spot and you can then factorise.
Thanks in advance for any help!
I am having trouble with this equation:
2^(3*x)-3*2^(2*x)-6*2^x+8=0
My main problem is how to deal with the exponents that are multiplied by a constant, here:
2^(3*x)-3*2^(2*x)-6*2^x+8=0
I cant just multiply these can I ? and end up with 12^x and so on, can I?
Thank you!