Thanks in advance for any help!

I am having trouble with this equation:

2^(3*x)-3*2^(2*x)-6*2^x+8=0

My main problem is how to deal with the exponents that are multiplied by a constant, here:

2^(3*x)-3*2^(2*x)-6*2^x+8=0

I cant just multiply these can I ? and end up with 12^x and so on, can I?

Thank you!