I've run into another logarithmic equation I'm not sure how to go about solving. Would appreciate a hint or guidelines: Solve the equation. (Round your answer to four decimal places.) e^{x} − 30e^{−x} − 1 = 0 Thanks.
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Originally Posted by FatimaA I've run into another logarithmic equation I'm not sure how to go about solving. Would appreciate a hint or guidelines: Solve the equation. (Round your answer to four decimal places.) e^{x} − 30e^{−x} − 1 = 0 Thanks. start by multiplying each term by $\displaystyle e^x$ ... then deal w/ the resulting quadratic (in $\displaystyle e^x$)
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