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Math Help - Solving x values for logarithmic equation.

  1. #1
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    Solving x values for logarithmic equation.

    I would really appreciate some help with this problem. I don't know how to factor or use log to get the x values. I haven't run into a problem like this before.

    Solve the equation. (Round your answers to four decimal places.)

    x2e2x + 6xe2xe2x = 0

    Thanks for the help in advance.
    Last edited by FatimaA; June 7th 2012 at 03:21 PM.
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  2. #2
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    Re: Solving x values for logarithmic equation.

    Quote Originally Posted by FatimaA View Post
    I would really appreciate some help with this problem. I don't know how to factor or use log to get the x values. I haven't run into a problem like this before.

    x2e2x + 6xe2xe2x = 0

    Thanks for the help in advance.
    e^{2x}(x^2+6x-1) = 0

    since e^{2x} > 0 for all x, only the quadratic factor can equal 0

    quadratic formula?
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  3. #3
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    Re: Solving x values for logarithmic equation.

    x = .1623

    x = -6.1623

    Both were correct. Thanks for the help.
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  4. #4
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    Re: Solving x values for logarithmic equation.

    Quote Originally Posted by FatimaA View Post
    x = .1623

    x = -6.1623

    Both were correct. Thanks for the help.
    did you really need the calculator?

    x = -3 \pm \sqrt{10}
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  5. #5
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    Re: Solving x values for logarithmic equation.

    I had to input the answers as decimals into the computer - that's the only way it accepts them.
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