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Math Help - Need help with Logarithm Problem

  1. #1
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    Need help with Logarithm Problem

    Here is the problem:


    e^4x+3=11

    I have pages of work and have looked through my books for clues, but I think I may be thinking about this one wrong. Can anyone help? Thanks.
    Last edited by captaininsano; June 6th 2012 at 12:50 PM. Reason: copied problem wrong
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  2. #2
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    Re: Need help with Logarithm Problem

    Quote Originally Posted by captaininsano View Post
    Here is the problem:

    2e^(3x)+5=10

    I have pages of work and have looked through my books for clues, but I think I may be thinking about this one wrong. <--- it would be much easier for us to help you if we have some information about your thinking!
    Can anyone help? Thanks.
    2e^{3x} + 5=10

    2e^{3x} =5

    e^{3x} =2.5

    3x=\ln(2.5)

    Solve for x.
    Thanks from captaininsano
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  3. #3
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    Re: Need help with Logarithm Problem

    1. Subtract 5 from both side. 2e^(3x)=5
    2. Divide both sides by 2. e^(3x)=5/2
    3. Take the natural logarithm from both side. 3x=ln(5/2)
    4. Divide both sides by 3. x=1/3*ln(5/2)
    5. Check the solution.
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  4. #4
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    Re: Need help with Logarithm Problem

    Quote Originally Posted by captaininsano View Post
    Here is the problem:


    e^4x+3=11
    e^{4x} + 3 = 11

    or

    e^{4x+3} = 11

    ?
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  5. #5
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    Re: Need help with Logarithm Problem

    The first one, should have put 4x in parentheses. Sorry.
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  6. #6
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    Re: Need help with Logarithm Problem

    1. Subtract the 3 from both sides. e^(4x)=8
    2. Taking the Natural Logarithm both sides and Simplify. 4x=ln(8), 4x=3ln(2)
    3. Divide by 4. x=3/4*ln(2).
    4. Check the solution.
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