(2^x) - 6/(2^-x)=6
Hello, sluggerbroth!
(2^x) - 6/(2^-x) = 6
I suspect that the problem is: .
Multiply by
And we have: . . . . a quadratic in
Quadratic Formula: .
Take logs, base 10: .
. . . . . . . . . . . . . .
n . . . . . . . . . . . . . . . . . .
Note that is negative.