(2^x) - 6/(2^-x)=6

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- Jun 3rd 2012, 05:24 AMsluggerbrothsolve in logs to base 10
(2^x) - 6/(2^-x)=6

- Jun 3rd 2012, 05:40 AMProve ItRe: solve in logs to base 10
- Jun 3rd 2012, 05:44 AMPlatoRe: solve in logs to base 10
- Jun 3rd 2012, 08:17 AMSorobanRe: solve in logs to base 10
Hello, sluggerbroth!

Quote:

(2^x) - 6/(2^-x) = 6

I suspect that the problem is: .

Multiply by

And we have: . . . . a quadratic in

Quadratic Formula: .

Take logs, base 10: .

. . . . . . . . . . . . . .

n . . . . . . . . . . . . . . . . . .

Note that is negative.