A driver makes same trip everyday.he meets three trafic lights on trip. A study established that :

The probability of meeting three red lights is 0.2

The pobability of meeting atleast one red light is 0.8

The probability of meeting one red light is 0.3

Give the probability :

A:"meet exactly two red lights

B:"does not meet a red light"

C:"meet at most one red light"

I solved it as follows but am not sure :

A:0.3*0.3=0.09

B:1-0.2=0.8

C:1-0.8=0.2

Please help