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    Probability question

    A 6 sided die having its side numbered from 1 till 6 is tricked such that the probability of appearence of each side is proportional to its number.
    What is the probability of each of the numbers 1,2,3,4,5 and6???
    Last edited by lebanon; May 22nd 2012 at 08:29 AM.
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    Re: Probability question

    Quote Originally Posted by lebanon View Post
    A 6 sided die having its side numbered from 1 till 7 is tricked such that the probability of appearence of each side is proportional to its number.
    What is the probability of each of the numbers 1,2,3,4,5 and6???
    A six sided die numbered from 1 to 7???
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    Re: Probability question

    Sorry to 6
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    Re: Probability question

    Quote Originally Posted by lebanon View Post
    A 6 sided die having its side numbered from 1 till 6 is tricked such that the probability of appearence of each side is proportional to its number.
    What is the probability of each of the numbers 1,2,3,4,5 and6???
    Change the model. Think of a box of numbered cards with one 1, two 2's, \cdots, six 6's.
    Now draw out one card, note its number, return it to the box. Shuffle well.
    What is the probability of each of the numbers 1,2,3,4,5 and 6?
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    Re: Probability question

    Quote Originally Posted by Plato View Post
    Change the model. Think of a box of numbered cards with one 1, two 2's, \cdots, six 6's.
    Now draw out one card, note its number, return it to the box. Shuffle well.
    What is the probability of each of the numbers 1,2,3,4,5 and 6?
    p(1)=1/21
    p(2)=2/21
    P(3)=3/21
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    .
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    am i right ?
    Last edited by lebanon; May 22nd 2012 at 09:16 AM.
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    Re: Probability question

    Quote Originally Posted by lebanon View Post
    1/6 each ???
    Your edit is correct for my model,
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