# Help with finding the possible x values of an equation.

• May 20th 2012, 03:10 AM
AshleeG96
Help with finding the possible x values of an equation.
Hey there I was wondering if anyone could please tell me the domain of this equation,

T= 60-2400( 1 )
(x + 100 )

Thanks!(Rofl)
• May 20th 2012, 04:06 AM
Prove It
Re: Help with finding the possible x values of an equation.
Quote:

Originally Posted by AshleeG96
Hey there I was wondering if anyone could please tell me the domain of this equation,

T= 60-2400( 1 )
(x + 100 )

Thanks!(Rofl)

Is this \displaystyle \displaystyle \begin{align*} T = 60 - 2400\left(\frac{1}{x + 100}\right) \end{align*}?
• May 20th 2012, 04:10 AM
AshleeG96
Re: Help with finding the possible x values of an equation.
Yeah that I didn't know how to do that.
• May 20th 2012, 04:11 AM
Prove It
Re: Help with finding the possible x values of an equation.
The function will be defined for all x that do not make the denominator equal to 0.
• May 20th 2012, 04:12 AM
AshleeG96
Re: Help with finding the possible x values of an equation.
Simple terms please? I'm not very good at mathematical lingo. Sorry. :(
• May 20th 2012, 04:17 AM
Prove It
Re: Help with finding the possible x values of an equation.
If you don't know what a denominator is then you should not be taking advanced high school algebra...
• May 20th 2012, 04:20 AM
AshleeG96
Re: Help with finding the possible x values of an equation.
I'm no taking advanced algebra, I'm taking normal grade 11 math. I have to pass this in order to get my highschool certificate and go to university.
• May 20th 2012, 04:51 AM
skeeter
Re: Help with finding the possible x values of an equation.
You've asked a question about the domain of a function without knowing what it means. If/when you enter a University, you'll be expected to try and answer questions on your own, without someone telling you the answer outright. This is the first step in becoming an independent learner. To prepare you for this eventuality, I recommend you do some research of your own on the topic of "domain of a function". Try a google search.
• May 20th 2012, 04:55 AM
AshleeG96
Re: Help with finding the possible x values of an equation.
Deleting this thread obviously you guys hate people that need help and aren't on the same level of math you are. Thanks guys for all your unwanted comments and not your helpfulness and I have actually done my math well, I have been getting above average in all my tests, so whatever obviously you know more about me than what I know about myself. By the way, who are you to judge since you're the one judging people on math forums. :) have a good day.
• May 20th 2012, 05:25 AM
Prove It
Re: Help with finding the possible x values of an equation.
Quote:

Originally Posted by AshleeG96
Deleting this thread obviously you guys hate people that need help and aren't on the same level of math you are.

Not true, we are here to help. My first post tells you the answer. If you know anything about a function is - a function works like a computer program, taking an input of numbers (the domain of the function) and doing something to get an output of numbers (the range).

This particular function has the input (x) in a fraction, so in order to answer your question, you need to know how fractions work.

Mathematics is like a skyscraper, you can't build the higher levels if your foundation is only a few matchsticks.

There is also a saying that fits: God helps those who help themselves. While those of us on the forum are not by any means gods, we are more willing to help if you've shown that you at least know some of what you're attempting and have tried to answer the question yourself.

Quote:

Thanks guys for all your unwanted comments and not your helpfulness and I have actually done my math well, I have been getting above average in all my tests, so whatever obviously you know more about me than what I know about myself. By the way, who are you to judge since you're the one judging people on math forums. :) have a good day.
I am a mathematics teacher, evaluation is part of the job description :)
• May 20th 2012, 05:56 AM