The equation is on the interval [0,2pi]:2cos^2x+3sinx-3=0
I get up to the part -2sinx^2+3sinx-1=0
I cant get past this, im stuck as to how i should factor it.
Can domeone also tell me if i can do this on the ti-nspire cas? If so, how?
The equation is on the interval [0,2pi]:2cos^2x+3sinx-3=0
I get up to the part -2sinx^2+3sinx-1=0
I cant get past this, im stuck as to how i should factor it.
Can domeone also tell me if i can do this on the ti-nspire cas? If so, how?
Wait, somethings still wrong...
The first equation is
-sinx-1=0
And that gives me
-sinx=1 and as per the even and odd identity it is the same as sinx=-1 correct?
So what would my ans be? 3pi/2?
And for the second equation, sin x =1/2 so would my ans be pi/6+2npi and 5pi/6+2npi?