Find the points on the graph of y = -csc(x), where the tangent is parallel to 3y-2x=4. Use exact values. 0 is less than or equal to x which is less than or equal to 2*pi Thanks
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Originally Posted by Mr_Green Find the points on the graph of y = -csc(x), where the tangent is parallel to 3y-2x=4. Use exact values. 0 is less than or equal to x which is less than or equal to 2*pi Thanks . To be parallel it means the derivative must be equal to 2/3. Now find all point with derivative 2/3.
so thh derivate of -csc is = So I set this equal to 2/3?
Originally Posted by Mr_Green so thh derivate of -csc is = So I set this equal to 2/3? Yes.
so i get pi/3 Is this correct? Is this the only point?
Last edited by Mr_Green; Oct 4th 2007 at 03:39 AM.
i found that out by plugging into my calculator and using the intersect ability on the graph. Is there anything mathematical that I could do to solve it?
Originally Posted by Mr_Green Find the points on the graph of y = -csc(x), where the tangent is parallel to 3y-2x=4. Use exact values. 0 is less than or equal to x which is less than or equal to 2*pi Thanks Originally Posted by Mr_Green so i get pi/3 Is this correct? Is this the only point? So we need to solve Let . Then this equation becomes: This has solutions: or Thus <-- Impossible for real x. or So there are two answers. -Dan
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Last edited by Mr_Green; Oct 5th 2007 at 10:52 AM.
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