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Math Help - Precalculus Problem

  1. #1
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    Precalculus Problem

    Any help would really be appreciated:

    Express the distance from point (x,y) on the graph y = 4 - x^2 to the point (0,1) as a function of x. Give the domain of the function.

    2. compute the difference quotient for (f(x+h) - f(x))/h for f(x) = 3x + 8, and f(x) = 1/x^2
    Last edited by skabani; October 2nd 2007 at 03:43 PM.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by skabani View Post
    Any help would really be appreciated:

    Express the distance from point (x,y) on the graph y = 4 - x^2 to the point (0,1) as a function of x. Give the domain of the function.
    The distance formula says the distance, d(x,y), between two points (x_1, y_1) and (x_2,y_2) is given by:

    d(x,y) = \sqrt {(x_2 - x_1)^2 + (y_2 - y_1)^2}




    Hint:

    For the graph y = 4 - x^2, any arbitrary point (x,y) on the graph can be represented as \left( x,4 - x^2 \right)
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  3. #3
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    so would the answer be the square root of x^4 -7x^2 - 2x + 15 ??
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by skabani View Post
    so would the answer be the square root of x^4 -7x^2 - 2x + 15 ??
    no. look at the formula again. there should be no x's in your answer, the lowest power of x would be 2 when you square the things in the brackets
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  5. #5
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    so then would it be the square root x^4 - 7x^2 + 9?

    and could you help me with the function problems too..

    for the first one, f(x) = -3x + 8, i got 1
    and for the second one, f(x) = 1/x^2, i got (-2x-h)/[(x^2)(x+h)^2]

    thanks for all ur help!!
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