Thread: converting into differnce of logarithms.

ln((x+6)(x-8))/(x-7)^2)^5/3 , x > 8

You have too many closing parentheses.

As emakarov said, the problem has unmatched parentheses- it is impossible to tell if the entire logarithm is to the 5/3 power, or just the argument of the logarithm, or just the denominator.

But to answer your question generally, log(A/B)= log(A)- log(B). It is also true that log(AB)= log(A)+ log(B) and that log(A^n)= nlog(A). You may need to use those.

I noticed that, :/, I don't know how to enter formulas to where they actually look like they are written.

its suppose to be, ln( ((x+6)(x-8))/(x-7)^2)^5/3 , x > 8

Originally Posted by blondedude092

its suppose to be, ln( ((x+6)(x-8))/(x-7)^2)^5/3 , x > 8