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Thread: find equation of last parabola

  1. April 27th 2012, 05:47 PM #1
    sluggerbroth
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    find equation of last parabola

    Contains points (1,10) and (2,4), axis of symmetry is vertical, vertex is on line4x-3y=6
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  2. April 27th 2012, 09:14 PM #2
    princeps
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    Re: find equation of last parabola

    Hint :

    y=ax^2+bx+c

    V\left(\frac{-b}{2a},\frac{-D}{4a}\right)

    D=b^2-4ac
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