is bijective if and only if , the equation has an unique solution
Now, let
okay, so i need to determine whether or not f is one-to-one and onto. if so, find f^-1.
im pretty sure i can do it, i just dont know how to read the thing.
A=R \ {0} and B=R \ {2} and f: A->B
f(x)= 1/x + 2
where R is the reals. can anyone please explain to me how to read that?