1. vectors question #4

2. Originally Posted by afeasfaerw23231233

-Dan

3. i cannot find the value of 'lambda'
it seems that you cannot see my image, would you please click on the following link to get my question?

my question is here

4. Originally Posted by topsquark

-Dan
Sorry. The first attachment didn't load when I first visited this thread.

-Dan

5. Originally Posted by afeasfaerw23231233

a)
OC = OA + AC = a + 2b

BC = BO + OC = (-b) + (a + 2b) = a + b

OQ = OB + BQ = OB + (1/3)BC = b + (1/3)(a + b) = (1/3)a + (4/3)b

b)
i) OR = OP + PR = (1/2)OA + hPQ

Now, PQ = PO + OQ = -(1/2)OA + OQ = -(1/2)a + (1/3)a + (4/3)b = -(1/6)a + (4/3)b

So
OR = (1/2)OA + hPQ = (1/2)a + h[-(1/6)a + (4/3)b]
(I'll let you simplify that.)

ii)
OR = k OC
(1/2)a + h[-(1/6)a + (4/3)b] = k[a + 2b]

From here equate the coefficients of a on each side of the equation and the coefficients of b on each side of the equation. Two equations in two unknowns, h and k, so you can solve this.

I have to go. See if you can carry on from here.

-Dan