Here is the given question:

(a) Sketch the level curves of z = (x^2 - 2y +6)/(3x^2 + y) at heights z = 0 and z =1.

(b) Sketch the surface (x−1)^2 + (y+2)^2 + z^2 = 2 in R^3. Write down a point which is on the surface.

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(a) I set z = 0 and then sketched the level curve. I got a positive parabola, intersecting the y-axis at 3 (no roots). Is that correct?

For z = 1, I got a negative parabola, intersecting the y-axis at 2, with roots -2 and 2. Is that correct? Also, would I draw each level curve on separate axes or on the same one?

(b) I set two variables, x = 2, y = -2 and therefore, z = 1. I then substituted them into the equation and with it equal to 2, so (2, -2, 1) as a point on the surface of this sphere. Moreover, center is (1, -2, 0) and the radius is √2. However, I am confused with sketching the curve. How would I arrange the axes to sketch the sphere? Since y = -2, it exists on the negative y axis. & I assume you would arrange the axes (appropriately and correctly) so that it forms a cube for the sphere to be within, right? That, I'm unsure of how to do as would all the axes still meet at the origin?