I need help with this problem..even asked several friends but no1 knows what to do :[ heres a little picture so the answer is: 6 - (square- root-10) .. but i have no clue how to even get that.
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We have $\displaystyle OA=R, \ OB=R-1, \ AB=5-R$ Apply Pitagora in AOB: $\displaystyle R^2=(R-1)^2+(5-R)^2\Rightarrow R^2-12R+26=0$ Solving for R, the good solution is $\displaystyle R=6-\sqrt{10}$
oh wow, thank you very much
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