Just a quick question. Is it correct to say that: $\displaystyle \frac{45 - (2/3)(r^2)}{r}$ = $\displaystyle \frac{45 - 3r^2}{2r}$
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Originally Posted by GrigOrig99 Just a quick question. Is it correct to say that: $\displaystyle \frac{45 - (2/3)(r^2)}{r}$ = $\displaystyle \frac{45 - 3r^2}{2r}$ no, more like ... $\displaystyle \frac{45 - (2/3)(r^2)}{r} \cdot \frac{3}{3} = \frac{135 - 2r^2}{3r}$
Ok, ty.
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