Results 1 to 6 of 6

- March 27th 2012, 12:57 PM #1

- Joined
- Mar 2012
- From
- europe
- Posts
- 3

- March 27th 2012, 01:09 PM #2

- March 27th 2012, 01:55 PM #3

- Joined
- Apr 2005
- Posts
- 18,054
- Thanks
- 2381

- March 27th 2012, 01:56 PM #4

- Joined
- Mar 2012
- From
- europe
- Posts
- 3

- March 27th 2012, 01:59 PM #5

- Joined
- Apr 2005
- Posts
- 18,054
- Thanks
- 2381

## Re: logaithm help.

??? You will accept 3> 1 won't you? And square root is an increasing function so . In fact, it is not at all difficult to use a calculator to see that .

Or do you mean " "?

Obviously both and give the same thing and**provided**that a is positive becauser log(a) is not defined for negative a.

- March 27th 2012, 02:00 PM #6

- Joined
- Mar 2012
- From
- europe
- Posts
- 3

## Re: logaithm help.

Emm, I think you got me a little bit wrong here, I was just wondering why did we have to write sqrt(3)-1 instead of 1-sqrt(3).

Edit: Ah yeah, I totally forgot about looking at that part. Thank you.