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- Mar 27th 2012, 01:57 PM #1

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- Mar 27th 2012, 02:09 PM #2

- Mar 27th 2012, 02:55 PM #3

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- Mar 27th 2012, 02:56 PM #4

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- Mar 27th 2012, 02:59 PM #5

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## Re: logaithm help.

??? You will accept 3> 1 won't you? And square root is an increasing function so . In fact, it is not at all difficult to use a calculator to see that .

Or do you mean " "?

Obviously both and give the same thing and**provided**that a is positive becauser log(a) is not defined for negative a.

- Mar 27th 2012, 03:00 PM #6

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## Re: logaithm help.

Emm, I think you got me a little bit wrong here, I was just wondering why did we have to write sqrt(3)-1 instead of 1-sqrt(3).

Edit: Ah yeah, I totally forgot about looking at that part. Thank you.