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Math Help - Please check My results !

  1. #1
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    Please check My results !

    Hello please tell me if i did my homework right, because i think my math teacher hates me lol anyway here we go:

    the question:
    for which of values of entirer natural N T one has:

    [1+i (racing) 3] ^n real positive?

    [1+i (racine) 3] ^n real negative?

    [1+i (racing) 3] ^n imaginary pure?


    for me the first 1 I got:
    -postitive: n=6k (pi)

    - negative: n=3+6k

    to imaginair pure:
    n/3=1/2+k = 2k/2 +1



    P.S: (racine) =

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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by iceman1 View Post
    Hello please tell me if i did my homework right, because i think my math teacher hates me lol anyway here we go:

    the question:
    for which of values of entirer natural N T one has:

    [1+i (racing) 3] ^n real positive?

    [1+i (racine) 3] ^n real negative?

    [1+i (racing) 3] ^n imaginary pure?


    for me the first 1 I got:
    -postitive: n=6k (pi)

    - negative: n=3+6k

    to imaginair pure:
    n/3=1/2+k = 2k/2 +1



    P.S: (racine) =

    "racine?" How about "radical" maybe?

    And what does " for which of values of entirer natural N T one has" mean?

    -Dan
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  3. #3
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    Quote Originally Posted by topsquark View Post
    "racine?" How about "radical" maybe?

    And what does " for which of values of entirer natural N T one has" mean?

    -Dan
    sorry lol iam a french educated so i don't know the meaning in english.

    '' for which of values of entirer natural N T one has"''
    prove :
    [1+i (racing) 3] ^n real positive?

    [1+i (racine) 3] ^n real negative?

    [1+i (racing) 3] ^n imaginary pure?


    i got the module of z and the argument , then i replaced and i finished by this
    -postitive: n=6k (pi)

    - negative: n=3+6k

    to imaginair pure:
    n/3=1/2+k = 2k/2 +1
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