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Math Help - Simplify expression

  1. #1
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    Simplify expression

    6y^-2(2y^4)^-3
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  2. #2
    Super Member Quacky's Avatar
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    Re: Simplify expression

    x^{-1}=\frac{1}{x}

    x^{-2}=\frac{1}{x^2}

    x^{-a}=\frac{1}{x^a}

    (x^a)^b=x^{ab}

    Please show your attempt at using the above statements to simplify your expression.
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  3. #3
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    Re: Simplify expression

    Quote Originally Posted by Dobby View Post
    6y^-2(2y^4)^-3
    6y^{-2} \cdot (2y^4)^{-3}=\frac{6}{y^2} \cdot \frac{1}{(2y^4)^3}=\frac{6}{y^2} \cdot \frac {1}{2^3 \cdot (y^4)^3}=

    = \frac{6}{y^2} \cdot \frac{1}{8 \cdot y^{12}}=\frac{3}{4}\cdot \frac{1}{y^{16}}=\frac{3}{4} \cdot y^{-16}
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  4. #4
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    Re: Simplify expression

    Quote Originally Posted by princeps View Post
    6y^{-2} \cdot (2y^4)^{-3}=\frac{6}{y^2} \cdot \frac{1}{(2y^4)^3}=\frac{6}{y^2} \cdot \frac {1}{2^3 \cdot (y^4)^3}=

    = \frac{6}{y^2} \cdot \frac{1}{8 \cdot y^{12}}=\frac{3}{4}\cdot \frac{1}{y^{16}}=\frac{3}{4} \cdot y^{-16}
    Correct
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  5. #5
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    Re: Simplify expression

    [QUOTE=princeps;710102] 6y^{-2} \cdot (2y^4)^{-3}=\frac{6}{y^2} \cdot \frac{1}{(2y^4)^3}=\frac{6}{y^2} \cdot \frac {1}{2^3 \cdot (y^4)^3}=

    = \frac{6}{y^2} \cdot \frac{1}{8 \cdot y^{12}}=\frac{3}{4}\cdot \frac{1}{y^{16}}=\frac{3}{4} \cdot y^{-16}[/QUOTE



    typo error
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