The question is:

Given that $\displaystyle \ln(2x^2+9x-5)=1+\ln(x^2+2x-15)$, find $\displaystyle x$ in terms of $\displaystyle e$

I got as far as:

$\displaystyle e = \dfrac{2x-1}{x-3}$

The next step is

$\displaystyle e = \dfrac{2x-1}{x-3} \Rightarrow 3e - 1 = x(e - 2)$

I'm probably just being dense, but I don't know how to do that step. Could somebody please help me.

Thank you