Compute the sum of the digits of the number given by If a<b, ab = 6 and a + b = 5. I was putting a = 5-b and substitute in but unable to solve it. Appreciate if you show me how to solve it.
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Originally Posted by stevecowall If a<b, ab = 6 and a + b = 5. you have $\displaystyle a=5-b$ so $\displaystyle (5-b)b=6 \implies b^2-5b+6=0$ Can you solve this quadratic?
Welcome to MHF, stevecowall! How many ways do you know to factorize ab=6?
Thank you I have figure it out already thanks so much
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