If f(x) = Mod(x), 0<Mod(x)<=2 1 x=0 Is there any local extremum at x=0.
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By "mod(x)", do you mean "absolute value of x", |x|? If so, your function is f(x)= |x| for and while f(0)= 1. Yes, x= 0 is a local maximum since f(0)= 1 is larger than f(x) for x close to, but not equal to 0.
Originally Posted by deepak If f(x) = Mod(x), 0<Mod(x)<=2 1 x=0Is there any local extremum at x=0. If you mean , then there is a local maximum at because in a neighborhood of . Edited: Sorry, I didn't see HallsofIvy post.
Last edited by FernandoRevilla; December 27th 2011 at 04:41 AM.
It was probably posted while you were typing your resonse!
Originally Posted by HallsofIvy It was probably posted while you were typing your resonse! Both of us at 2:26 PM, but you are helper, so your post appeared before mine
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