If log_b 6 = .4040 then b^-.4040 is equal to...I am not to sure about how to solve this.

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- December 18th 2011, 02:34 PMBashyboyEvaluating log
If log_b 6 = .4040 then b^-.4040 is equal to...I am not to sure about how to solve this.

- December 18th 2011, 02:37 PMPlatoRe: Evaluating log
- December 18th 2011, 03:10 PMBashyboyRe: Evaluating log
Well, the exponent on b is negative, does that change the definition you gave me at all?

- December 18th 2011, 03:14 PMPlatoRe: Evaluating log
- December 18th 2011, 03:28 PMBashyboyRe: Evaluating log
Oh, yes--I undserstand now. I do have another one, though: If log 2 = .3010 then log sqroot(20) is equal to.

- December 18th 2011, 03:44 PMPlatoRe: Evaluating log
- December 18th 2011, 03:57 PMBashyboyRe: Evaluating log
Do I sense condescension in your writing, or am I thoroughly mistaken?

- December 18th 2011, 04:33 PMPlatoRe: Evaluating log
- December 18th 2011, 04:49 PMBashyboyRe: Evaluating log
No, I am absolutely not angry. I inferred that impression on my first reading of your post; but, after re-reading it, I have found that impression to be wrong. I am terrible sorry. I sensitive when it comes to scorning my mathematical knowledge; and I know it is scarce, due to myself having studied it a little later in life than normal, and that is why I was a bit jumpy. Again, sorry.