1. Focus of parabola

x^2-ky+3=0 represents a parabola whose focus is in (0,2) find k

2. Re: parabola

Originally Posted by prasum
x^2-ky+3=0 represents a parabola whose focus is in (0,2) find k
$\displaystyle T\left(\frac{-b}{2a},\frac{-D}{4a}\right)=(0,2)$

$\displaystyle a=\frac{1}{k} , b =0 , c=\frac{3}{k} , D=b^2-4ac$

3. Re: parabola

can yu tell me what will be the value of k 2 ,4,6 or 3

4. Re: parabola

What have you tried? Princeps post tell's what you have to do, namely:
The equation of the parabola is:
$\displaystyle y=\frac{x^2+3}{k}$
Therefore we can find $\displaystyle k$ by solving the equation:
$\displaystyle \frac{-D}{4a}=2 \Rightarrow \frac{4ac-b^2}{4a}=2$

Proceed.