0 <= e^(-x) < 1
I have to find the solution set so i got:
minus infinity > x > 0
correct?
and for
|2-3x|<3
i get
x > 1/3
and
x < 5/3
now my question is:
on the second inequality, the solution set is the INTERSECTION of both solutions? (is it an OR or and AND connection of both sets?)