0 <= e^(-x) < 1

I have to find the solution set so i got:

minus infinity > x > 0

correct?

and for

|2-3x|<3

i get

x > 1/3

and

x < 5/3

now my question is:

on the second inequality, the solution set is the INTERSECTION of both solutions? (is it an OR or and AND connection of both sets?)