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Re: inverse trig indentities

all of these values are on the unit circle ... review the domain and range of the inverse trig functions.

Re: inverse trig indentities

Yes,

Can you be more exact about what you're confused?

To evaluate (for example):

Use the identity:

Honestly, I don't know what you mean by 'evaluete the expression by sketching a triangle'?

Re: inverse trig indentities

yeah, I'm not sure what it means by that either. And, I just don't understand how you got from tan [2 arctan (5/13)] to the identity you listed.

Re: inverse trig indentities

Quote:

Originally Posted by

**butlerw2** yeah, I'm not sure what it means by that either. And, I just don't understand how you got from tan [2 arctan (5/13)] to the identity you listed.

you need to understand that the output of an inverse trig function is an angle.

so ...

you now use the double angle identity for tangent that **Siron** posted and evaluate the value of .