1. ## 93.3 megahertz

if a radio station is broadcasting at a frequency of $92.3$ MHZ, or $92.3 \times 10^6$ cycles per second. What is the period of a wave with this frequency?
the ans to this is $108\times10^{-8}$sec

don't understand basically what the difference is between cycle and period or the relation of hertz and cycle other wise probably pretty easy to solve.

2. ## Re: 93.3 megahertz

Originally Posted by bigwave
if a radio station is broadcasting at a frequency of $92.3$ MHZ, or $92.3 \times 10^6$ cycles per second. What is the period of a wave with this frequency?
the ans to this is $108\times10^{-8}$sec

don't understand basically what the difference is between cycle and period or the relation of hertz and cycle other wise probably pretty easy to solve.

The frequency is $92.3 \times 10^6$ cycles per second which is the same as $92.3 \times 10^6$ Hz.
The time for one cycle is the period. It is 1 second divided by number of cycles per second = $\frac{1}{92.3 \times 10^6} = ....$ seconds.