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Thread: Integration by substitution #2

  1. December 1st 2011, 10:27 AM #1
    sakuraxkisu
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    Integration by substitution #2

    Hi, I have a question which involves integration by substitution:

    \int \frac{y\,(y-8)}{(y-4)^2} dy

    using the substitution u = y - 4

    The answer is
    \frac{y^2-8y+32}{y-4}+c

    But I keep on getting
    \frac{y^2-4y+16}{y-4}+c

    Any help would be greatly appreciated
    Last edited by mr fantastic; December 1st 2011 at 12:19 PM. Reason: Title.
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  2. December 1st 2011, 10:40 AM #2
    sakuraxkisu
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    Re: Integration by substitution

    By the way, I wasn't sure if I should've posted this here or in the university calculus section, as I'm not actually in university, but the american education system is different to where I live, so I got a bit confused haha!
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  3. December 1st 2011, 11:09 AM #3
    Quacky
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    Re: Integration by substitution

    Quote Originally Posted by sakuraxkisu View Post
    By the way, I wasn't sure if I should've posted this here or in the university calculus section, as I'm not actually in university, but the american education system is different to where I live, so I got a bit confused haha!
    All calculus questions belong in the "calculus" subforum, regardless of your current level of study.
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