# Thread: Integration by substitution #2

1. ## Integration by substitution #2

Hi, I have a question which involves integration by substitution:

$\displaystyle \int \frac{y\,(y-8)}{(y-4)^2} dy$

using the substitution u = y - 4

$\displaystyle \frac{y^2-8y+32}{y-4}+c$

But I keep on getting
$\displaystyle \frac{y^2-4y+16}{y-4}+c$

Any help would be greatly appreciated

2. ## Re: Integration by substitution

By the way, I wasn't sure if I should've posted this here or in the university calculus section, as I'm not actually in university, but the american education system is different to where I live, so I got a bit confused haha!

3. ## Re: Integration by substitution

Originally Posted by sakuraxkisu
By the way, I wasn't sure if I should've posted this here or in the university calculus section, as I'm not actually in university, but the american education system is different to where I live, so I got a bit confused haha!
All calculus questions belong in the "calculus" subforum, regardless of your current level of study.