$\displaystyle (e^z-1)(e^z-i)=0$

Can $\displaystyle e^z$ be isolated in any way?

I need to find all the solutions for $\displaystyle e^z$

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- Nov 28th 2011, 07:04 AM #1

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- Nov 28th 2011, 07:07 AM #2
## Re: Can this be writen any differently?

Do you mean you want something of the form $\displaystyle e^z=...$? Yes, you're dealing with an equation of the form $\displaystyle a\cdot b=0$ which implies that $\displaystyle a=0 \ \mbox{or} \ b=0$ are the solutions.

- Nov 28th 2011, 07:08 AM #3

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- Nov 28th 2011, 07:11 AM #4

- Nov 28th 2011, 07:14 AM #5

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- Nov 28th 2011, 07:20 AM #6

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- Nov 28th 2011, 07:22 AM #7
## Re: Can this be writen any differently?

- Nov 28th 2011, 07:27 AM #8

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## Re: Can this be writen any differently?

- Nov 28th 2011, 07:38 AM #9

- Nov 28th 2011, 07:42 AM #10

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- Nov 28th 2011, 07:48 AM #11

- Nov 28th 2011, 07:58 AM #12

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## Re: Can this be writen any differently?

- Nov 28th 2011, 08:05 AM #13