# How do you find the limits, holes, and vertical asymptotes of rational functions?

• Nov 27th 2011, 03:27 PM
david213
How do you find the limits, holes, and vertical asymptotes of rational functions?
f(x)=x^2+4/x^2-5x-6
• Nov 27th 2011, 03:33 PM
Plato
Re: How do you find the limits, holes, and vertical asymptotes of rational functions?
Quote:

Originally Posted by david213
f(x)=x^2+4/x^2-5x-6

Given $\frac{x^2+4}{x^2-5x-6}$.
There are no zeros for the numerator.
Both $-1~\&~6$ are zeros for the denominator.
Start there.
• Nov 27th 2011, 03:43 PM
david213
Re: How do you find the limits, holes, and vertical asymptotes of rational functions?
f(x)=x^2+4/(x-6)(x+1)

The vertical asymptotes are x=-1 x=6