The following exponentiation:
3e^(1+pi i)
Needs to be written in rectangular notation:
a + ib
Where "i" is the imaginary unit.
This is what I've found out myself so far:
I know that in order to find "a" and "b" I can use the argument "v" in the exponential notation:
re^(iv)
a = cos(v)
b = sin(v)
I also know that e^(iv1+iv2) = e^(iv1) * e^(iv2)
So if I try to apply these rules I get:
3e^(1+pi i) = 3e^1 * 3e^pi
Now calculating "a" I get:
a = 3*cos(1) * 3*cos(pi) = 3*cos(1) * -3
And for "b":
b = 3*sin(1) * 3*sin(pi) = 0
But I get the feeling that 3*cos(1) is wrong.