complex inequalities

if |z|=3 is a circle, how do you know if the region outside the circle is
|z|<3

Many thanks

Quote:

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Originally Posted by minicooper58

if |z|=3 is a circle, how do you know if the region outside the circle is |z|<3 .

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is the distance between .

Thus is a circle centered at the origin with radius 3.

BUT the exterior of that circle is , not it is not .

Hi , the question and answer is in the attachments . sorry i didn't fully explain the transformation part . I don't understand how the region is outside the circle for (b) .

Many thanks

That's not at all the question you originally asked! The set |z|< 3 is the inside of the circle given by |z|= 3. But the function maps the circle |z|= 3, with center at 0 and radius 3, into the circle with center at and radius . It also clearly maps 0 to 0. 0 is inside |z|< 3 but outside the circle with center and radius . Therefore, the interior of the first circle is mapped to the exterior of the second circle.