# Math Help - Simplifying log expression for y

1. ## Simplifying log expression for y

5^(y) = 2e^(y)

I proceeded to take the natural log of both sides, so yln(5) = ln2e(y) Where do I go from here?

2. ## Re: Simplifying log expression for y

Originally Posted by benny92000
5^(y) = 2e^(y)

I proceeded to take the natural log of both sides, so yln(5) = ln2e(y) Where do I go from here?
Use the log addition rule to separate the RHS: $\ln(2e^y) = \ln(2) + \ln(e^y) = \ln(2) + y$