# Simplifying log expression for y

• November 25th 2011, 12:28 PM
benny92000
Simplifying log expression for y
5^(y) = 2e^(y)

I proceeded to take the natural log of both sides, so yln(5) = ln2e(y) Where do I go from here?
• November 25th 2011, 12:39 PM
e^(i*pi)
Re: Simplifying log expression for y
Quote:

Originally Posted by benny92000
5^(y) = 2e^(y)

I proceeded to take the natural log of both sides, so yln(5) = ln2e(y) Where do I go from here?

Use the log addition rule to separate the RHS: $\ln(2e^y) = \ln(2) + \ln(e^y) = \ln(2) + y$