5^(y) = 2e^(y)

I proceeded to take the natural log of both sides, so yln(5) = ln2e(y) Where do I go from here?

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- November 25th 2011, 11:28 AMbenny92000Simplifying log expression for y
5^(y) = 2e^(y)

I proceeded to take the natural log of both sides, so yln(5) = ln2e(y) Where do I go from here? - November 25th 2011, 11:39 AMe^(i*pi)Re: Simplifying log expression for y