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• Sep 20th 2007, 01:33 PM
aikenfan
Problems 35, 36, 47, and 48 I have been having some trouble with....

35 and 36
For B...i had to find the zeros with a calculator
for part c, I had to find the zeros algebraically

47 and 48
i had to find the zeros and max and min with a calculator
for 47, i am a little confused about the +- part....

I do not know is I am doing these correctly...if someone could take a look at my work, it would be greatly appreciated

http://i103.photobucket.com/albums/m...919/111003.jpg
http://i103.photobucket.com/albums/m...n91919/111.jpg
• Sep 20th 2007, 02:29 PM
Jonboy
on 35 and 36 the c's look good. that's all i have time to check.
• Sep 21st 2007, 05:22 AM
topsquark
47 looks good.

Where's the second zero on 48? (Look on the +x side.) And don't understand why you can't find max's and min's on this one? (See below.)

-Dan
• Sep 22nd 2007, 04:39 PM
aikenfan
How do I simplify part C on 36? would it be Sqrt(2)?
• Sep 22nd 2007, 04:43 PM
aikenfan
I get 2 for the second zero on 48...max: (-2.1915, 19.688)...min: (-1.938E-6, 5)
• Sep 22nd 2007, 04:44 PM
aikenfan
How do you know to use +-
or just + or just minus for the zeros and extrema
• Sep 23rd 2007, 06:30 AM
aikenfan
I have another question, if maybe someone can help me
• Sep 23rd 2007, 07:28 AM
topsquark
Quote:

Originally Posted by aikenfan
How do I simplify part C on 36? would it be Sqrt(2)?

$\displaystyle \frac{10 \pm \sqrt{200}}{10}$

$\displaystyle = \frac{10 \pm \sqrt{2 \cdot 10^2}}{10}$

$\displaystyle = \frac{10 \pm 10 \sqrt{2}}{10}$

$\displaystyle = \frac{10(1 \pm \sqrt{2})}{10}$

$\displaystyle 1 \pm \sqrt{2}$

-Dan
• Sep 23rd 2007, 07:35 AM
topsquark
Quote:

Originally Posted by aikenfan
I get 2 for the second zero on 48...max: (-2.1915, 19.688)...min: (-1.938E-6, 5)

Check that zero. I'm getting it to be less than 2. (Or you might be rounding it off too severely.)

And take a look at that graph again: I'm getting two relative maxima, not one. However, what you have listed is good. (Though you could probably round that -1.938 x 10^(-6) to 0 if you wanted.)

-Dan
• Sep 23rd 2007, 07:36 AM
topsquark
Quote:

Originally Posted by aikenfan
How do you know to use +-
or just + or just minus for the zeros and extrema

I'm not sure what the question is? Do you have a specific example of a problem where you are confused?

-Dan
• Sep 23rd 2007, 07:36 AM
topsquark
Quote:

Originally Posted by aikenfan
I have another question, if maybe someone can help me

It would be best to start a new question in a new thread at this point, but go ahead! We're here to help.

-Dan
• Sep 23rd 2007, 09:21 AM
aikenfan
i get 1.93 now, for that second zero on 48, i see what i did wrong
• Sep 23rd 2007, 09:24 AM
aikenfan
on 48, for the other maxima, i get: (.915, 5.646)
• Sep 23rd 2007, 09:27 AM
aikenfan
I also forgot to simplify part c on 35.....i got 2 + or - sqrt(3)
• Sep 23rd 2007, 11:11 AM
topsquark
Quote:

Originally Posted by aikenfan
i get 1.93 now, for that second zero on 48, i see what i did wrong

Quote:

Originally Posted by aikenfan
on 48, for the other maxima, i get: (.915, 5.646)

Quote:

Originally Posted by aikenfan
I also forgot to simplify part c on 35.....i got 2 + or - sqrt(3)

These all look good to me! :)

-Dan
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