How do u find the image set for a function with no domain?

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- November 19th 2011, 03:36 AMOrlandoImage set of a function?
How do u find the image set for a function with no domain?

- November 19th 2011, 03:40 AMDevenoRe: Image set of a function?
you don't. a function without a domain is an empty function, with a "blank" graph.

put it this way, how many pairs (x,f(x)) can occur in such a function, when there is no possible "first coordinate"? - November 19th 2011, 03:47 AMOrlandoRe: Image set of a function?
I thought it was the lowest possible value for y and the highest possible vaule foe y??

- November 19th 2011, 04:51 AMPlatoRe: Image set of a function?
- November 19th 2011, 06:30 AMOrlandoRe: Image set of a function?
Sorry I am tring to find the image set of :

f(x)=1/4(x-1)^2 -9

In interval notation.

There is no domain given so I persume the answear would be

[-9, to infinity) Sorry don`t know how to us the symbol for infinity

Or am I completly of the mark - November 19th 2011, 06:40 AMPlatoRe: Image set of a function?
- November 19th 2011, 06:43 AMOrlandoRe: Image set of a function?
sorry the function is 1/4*(x-1)^2-9

sorry for how I have presented it still trying to get use to typing maths in a computer

- November 19th 2011, 06:48 AMHallsofIvyRe: Image set of a function?
Then that has "natural domain" of all real numbers. It's graph is a parabola with vertex at (1, 9), vertical axis, opening upward.

If a function is given without an explicit domain, unless stated to the contrary, the domain is taken to be the "natural domain"- the set of all real numbers for which it is possible to calculate the value. The natural domain of a polynomial is all real numbers. The natural domain of [1/(4(x-1)^2]- 9] is all real number except x= 1. That is because x= 1 would make the denominator of that fraction 0. - November 19th 2011, 06:49 AMPlatoRe: Image set of a function?
- November 19th 2011, 06:53 AMOrlandoRe: Image set of a function?
yes it is. Sorry for messing everyone about still getting my head round La Tex

- November 19th 2011, 06:55 AMPlatoRe: Image set of a function?
- November 19th 2011, 07:02 AMOrlandoRe: Image set of a function?
Thanks for everyones help. Going to learn how to use La Tex looks a great bit of software.