
Originally Posted by
some_nerdy_guy
Ok, so theoretically some equations can be treated as quadratic and we're supposed to solve by having u=b (the middle term) and multiply the middle term, and 'a,' by u.
For example......
x-[3*sqrt(x)]-4=0
then replace x with u, and u equals sqrt(x)
therefore.....u^2-3u-4=0
then once factored you get u+1=0 with u=-1 and u-4=0 with u=4.
and since we substitued sqrt(x) with u we square both -1 and 4 which means x= 1 or 16
This I understand, but how do you do that method with a problem where the exponents are in fraction form? Like this one.....
x^(1/2)-4x^(1/4)+2=0