A. 2ln2x=8

B. 2e^2x-3e^x=-1

C. 6e^-5x+13=15

I have no clue how to solve any of these, since I missed a pre-cal class and when you miss a pre-cal class.. Things hit the fan. Could anyone offer an explanation?

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- November 6th 2011, 05:52 PMJordan1608Solve For the Unknown (ln equation)
A. 2ln2x=8

B. 2e^2x-3e^x=-1

C. 6e^-5x+13=15

I have no clue how to solve any of these, since I missed a pre-cal class and when you miss a pre-cal class.. Things hit the fan. Could anyone offer an explanation? - November 6th 2011, 06:02 PMpickslidesRe: Solve For the Unknown (ln equation)
For the first one, divide both sides by 2, then take both sides to the power of e.

For the second make u= e^x, then solve the resulting quadratic.

For the third take 13 from both sides, divide both sides by 6 and then take the ln of both sides.

what do you get?