# Pre-Cal Test Review Questions

• Nov 6th 2011, 04:48 PM
Jordan1608
Pre-Cal Test Review Questions
http://i39.tinypic.com/j7c41s.jpg

I need help with questions 1 and 3.

For question 1, I've gotten as far as what is shown but I don't know where to go from there. As for question 3 I am completely clueless.
• Nov 6th 2011, 04:57 PM
TheChaz
Re: Pre-Cal Test Review Questions
3 is interesting...
Most common definitions of "continuous" (esp with respect to the real numbers) at a point require that the point BE IN THE DOMAIN.

So we have (-4, 4), as an open interval, outside of the domain. Some would distinguish this as "not continuous" versus "discontinuos".
• Nov 6th 2011, 05:05 PM
Jordan1608
Re: Pre-Cal Test Review Questions
What my pre-cal teacher meant by that was where the function stops, and I figured out that the y-intercept is the root of 16 (4) and that it stretches from -4 to 4, so I expressed the discontinuous parts to be from XE(-infinity,-4)V(4,infinity)

Now the second part of that question makes no sense to me. X/X-3 would cause the X to cancel out, leaving you with 0/3 and the graph would be blank. I typed it into my graphing calculator and that's all I came up with.
• Nov 7th 2011, 08:56 AM
SammyS
Re: Pre-Cal Test Review Questions
Quote:

Originally Posted by Jordan1608
What my pre-cal teacher meant by that was where the function stops, and I figured out that the y-intercept is the root of 16 (4) and that it stretches from -4 to 4, so I expressed the discontinuous parts to be from XE(-infinity,-4)V(4,infinity)

Now the second part of that question makes no sense to me. X/X-3 would cause the X to cancel out, leaving you with 0/3 and the graph would be blank. I typed it into my graphing calculator and that's all I came up with.

But, you don't have x/x-3, you have x/(x-3) . x does not cancel out for x/(x-3) .