Q.: Please see attachment.

In this case, the text book has included the answer. I have 3^n/2, they have just 3^n. Can someone help me figure out how to factor out the 2? Thank you.

Printable View

- Oct 14th 2011, 10:05 AMGrigOrig99Sequences and Series
Q.: Please see attachment.

In this case, the text book has included the answer. I have 3^n/2, they have just 3^n. Can someone help me figure out how to factor out the 2? Thank you. - Oct 14th 2011, 10:11 AMe^(i*pi)Re: Sequences and Series
- Oct 14th 2011, 10:12 AMTheChazRe: Sequences and Series
$\displaystyle \frac{3^{n+1}}{2} - \frac{3^n}{2} = \frac{3 \cdot 3^n}{2} - \frac{1 \cdot 3^n}{2} = \frac{(3 - 1) \cdot 3^n}{2} = ...$

edit: the biggest spoiler was that someone posted before me!

(Punch) - Oct 14th 2011, 11:03 AMGrigOrig99Re: Sequences and Series
Thanks for the help guys. I really appreciate it.