Well I just need help solving this equation:$\displaystyle 5^{\frac{x}{2}}-2^x=1$
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Originally Posted by sbhatnagar Well I just need help solving this equation:$\displaystyle 5^{\frac{x}{2}}-2^x=1$ 1. By first inspection x = 2 2. Since $\displaystyle 5^{\tfrac x2}$ and $\displaystyle 2^x$ are both increasing continuously this solution must be the only one.
I know that x = 2 but can you show me the steps also?
Originally Posted by sbhatnagar I know that x = 2 but can you show me the steps also? You were told that this was just from inspection...
Originally Posted by sbhatnagar I know that x = 2 but can you show me the steps also? The 'steps' are: $\displaystyle 5^{2/2}- 2^2= 5- 4= 1$.
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